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Solutions — Medium JEE chemistry MCQ

Plotting $1 / \Lambda_{\mathrm{m}}$ against $\mathrm{c} \Lambda_{\mathrm{m}}$ for aqueous solutions of a monobasic weak acid (HX) resulted in a straight line with y-axis intercept of $\mathrm{P}$ and slope of $\mathrm{S}$. The ratio $\mathrm{P} / \mathrm{S}$ is $\left[\Lambda_{\mathrm{m}}=\right.$ molar conductivity $\Lambda_{\mathrm{m}}^{\mathrm{o}}=$ limiting molar conductivity $\mathrm{c}=$ molar concentration $\mathrm{K}_{\mathrm{a}}=$ dissociation constant of $\mathrm{HX}$ ]
  1. A. $\mathrm{K}_{\mathrm{a}} \Lambda_{\mathrm{m}}^{\mathrm{o}}$
  2. B. $\mathrm{K}_{\mathrm{a}} \Lambda_{\mathrm{m}}^{\mathrm{o}} / 2$
  3. C. $2 \mathrm{~K}_{\mathrm{a}} \Lambda_{\mathrm{m}}^{\mathrm{o}}$
  4. D. $1 /\left(\mathrm{K}_{\mathrm{a}} \Lambda_{\mathrm{m}}^{\mathrm{o}}\right)$

Solution

The correct option is **A**.

CHEMISTRY

medium • PYQ Reworded
Question
Read carefully, then pick the best option.
Plotting 1/Λm1 / \Lambda_{\mathrm{m}} against cΛm\mathrm{c} \Lambda_{\mathrm{m}} for aqueous solutions of a monobasic weak acid (HX) resulted in a straight line with y-axis intercept of P\mathrm{P} and slope of S\mathrm{S}. The ratio P/S\mathrm{P} / \mathrm{S} is [Λm=\left[\Lambda_{\mathrm{m}}=\right. molar conductivity Λmo=\Lambda_{\mathrm{m}}^{\mathrm{o}}= limiting molar conductivity c=\mathrm{c}= molar concentration Ka=\mathrm{K}_{\mathrm{a}}= dissociation constant of HX\mathrm{HX} ]
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Solutions — Medium JEE Chemistry MCQ | MyGoalPrep