Solid State — Medium JEE chemistry MCQ
The packing efficiency of a body-centered cubic (BCC) unit cell is approximately:
- A. $52\%$
- B. $68\%$
- C. $74\%$
- D. $90\%$
Solution
In a BCC unit cell:
- Number of atoms per unit cell = 2
- Atoms touch along the body diagonal
Body diagonal = $\sqrt{3}a$ = $4r$ (where $a$ is edge length, $r$ is atomic radius)
So $a = \frac{4r}{\sqrt{3}}$
Volume of unit cell = $a^3 = \left(\frac{4r}{\sqrt{3}}\right)^3 = \frac{64r^3}{3\sqrt{3}}$
Volume of atoms = $2 \times \frac{4}{3}\pi r^3 = \frac{8\pi r^3}{3}$
Packing efficiency = $\frac{\text{Volume of atoms}}{\text{Volume of unit cell}} \times 100$
$$= \frac{\frac{8\pi r^3}{3}}{\frac{64r^3}{3\sqrt{3}}} \times 100 = \frac{8\pi \sqrt{3}}{64} \times 100$$
$$= \frac{\pi\sqrt{3}}{8} \times 100 = \frac{3.14 \times 1.732}{8} \times 100 = 68\%$$
