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Redox Reactions — Easy JEE chemistry MCQ

The oxidation state of Cr in $K_2Cr_2O_7$ is:
  1. A. $+6$
  2. B. $+3$
  3. C. $+7$
  4. D. $+4$

Solution

$2(+1) + 2x + 7(-2) = 0$ $2 + 2x - 14 = 0$ $x = +6$

CHEMISTRY

easy • PYQ Reworded
Question
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The oxidation state of Cr in K2Cr2O7K_2Cr_2O_7 is:
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Redox Reactions — Easy JEE Chemistry MCQ | MyGoalPrep