Kinetics — Medium JEE chemistry MCQ
LIST-I contains compounds and LIST-II contains reactions
LIST-I
(I) $\mathrm{H}_2 \mathrm{O}_2$
(II) $\mathrm{Mg}(\mathrm{OH})_2$
(III) $\mathrm{BaCl}_2$
(IV) $\mathrm{CaCO}_3$
LIST-II
(P) $\mathrm{Mg}\left(\mathrm{HCO}_{3}\right)_{2}+\mathrm{Ca}(\mathrm{OH})_{2} \rightarrow$
(Q) $\mathrm{BaO}_{2}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow$
(R) $\mathrm{Ca}(\mathrm{OH})_{2}+\mathrm{MgCl}_{2} \rightarrow$
(S) $\mathrm{BaO}_{2}+\mathrm{HCl} \rightarrow$
(T) $\mathrm{Ca}\left(\mathrm{HCO}_{3}\right)_{2}+\mathrm{Ca}(\mathrm{OH})_{2} \rightarrow$
Match each compound in LIST-I with its formation reaction(s) in LIST-II, and choose the correct option\
- A. I $\rightarrow$ Q; II $\rightarrow$ P; III $\rightarrow \mathrm{S}$; IV $\rightarrow$ R
- B. I $\rightarrow$ T; II $\rightarrow$ P; III $\rightarrow$ Q; IV $\rightarrow \mathrm{R}$
- C. I $\rightarrow$ T; II $\rightarrow$ R; III $\rightarrow$ Q; IV $\rightarrow$ P
- D. I $\rightarrow$ Q; II $\rightarrow$ R; III $\rightarrow \mathrm{S}$; IV $\rightarrow \mathrm{P}$
Solution
The correct option is **D**.