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KineticsHard JEE chemistry MCQ

The reaction of $\mathrm{K}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right]$ with freshly prepared $\mathrm{FeSO}_4$ solution produces a dark blue precipitate called Turnbull's blue. Reaction of $\mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]$ with the $\mathrm{FeSO}_4$ solution in complete absence of air produces a white precipitate $\mathbf{X}$, which turns blue in air. Mixing the $\mathrm{FeSO}_4$ solution with $\mathrm{NaNO}_3$, followed by a slow addition of concentrated $\mathrm{H}_2 \mathrm{SO}_4$ through the side of the test tube produces a brown ring. Among the following, the brown ring is due to the formation of
  1. A. $\left[\mathrm{Fe}(\mathrm{NO})_{2}\left(\mathrm{SO}_{4}\right)_{2}\right]^{2-}$
  2. B. $\left[\mathrm{Fe}(\mathrm{NO})_{2}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}\right]^{3+}$
  3. C. $\left[\mathrm{Fe}(\mathrm{NO})_{4}\left(\mathrm{SO}_{4}\right)_{2}\right]$
  4. D. $\left[\mathrm{Fe}(\mathrm{NO})\left(\mathrm{H}_{2} \mathrm{O}\right)_{5}\right]^{2+}$

Solution

The correct option is **D**.

CHEMISTRY

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Question
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The reaction of K3[Fe(CN)6]\mathrm{K}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right] with freshly prepared FeSO4\mathrm{FeSO}_4 solution produces a dark blue precipitate called Turnbull's blue. Reaction of K4[Fe(CN)6]\mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right] with the FeSO4\mathrm{FeSO}_4 solution in complete absence of air produces a white precipitate X\mathbf{X}, which turns blue in air. Mixing the FeSO4\mathrm{FeSO}_4 solution with NaNO3\mathrm{NaNO}_3, followed by a slow addition of concentrated H2SO4\mathrm{H}_2 \mathrm{SO}_4 through the side of the test tube produces a brown ring. Among the following, the brown ring is due to the formation of
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Kinetics — Hard JEE Chemistry MCQ | MyGoalPrep