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Ionic Equilibrium — Easy JEE chemistry MCQ

**[JEE Mains 2026]** What volume ratio of decimolar NH₄OH and decimolar NH₄Cl should be mixed to give a buffer solution of pH = 9.25 at 25°C? (Given: pKb of NH₄OH = 4.75)
  1. A. 1:1
  2. B. 2:1
  3. C. 1:2
  4. D. 3:1

Solution

pOH = 14 - pH = 14 - 9.25 = 4.75. Using Henderson equation for basic buffer: pOH = pKb + log([Salt]/[Base]). 4.75 = 4.75 + log([NH₄Cl]/[NH₄OH]). log([NH₄Cl]/[NH₄OH]) = 0, so [NH₄Cl]/[NH₄OH] = 1. Volume ratio = 1:1 (since both are 0.1 M).

CHEMISTRY

easy • PYQ Reworded
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[JEE Mains 2026] What volume ratio of decimolar NH₄OH and decimolar NH₄Cl should be mixed to give a buffer solution of pH = 9.25 at 25°C? (Given: pKb of NH₄OH = 4.75)
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Ionic Equilibrium — Easy JEE Chemistry MCQ | MyGoalPrep