Equilibrium — Easy JEE chemistry MCQ
The pH of a $0.001$ M HCl solution is:
- A. $3$
- B. $11$
- C. $1$
- D. $2$
Solution
HCl is a strong acid, completely dissociates.
$[H^+] = 0.001 = 10^{-3}$ M
pH $= -\log(10^{-3}) = 3$
CHEMISTRY
easy • PYQ Reworded
Question
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The pH of a M HCl solution is:
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