Bonding — Hard JEE chemistry MCQ
LIST-I contains metal species and LIST-II contains their properties.
LIST-I
(I) $\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]^{4-}$
(II) $\left[\mathrm{RuCl}_{6}\right]^{2-}$
(III) $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$
(IV) $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$
LIST-II
(P) $t_{2 \mathrm{~g}}$ orbitals contain 4 electrons
(Q) $\mu$ (spin-only $=4.9 \mathrm{BM}$
(R) low spin complex ion
(S) metal ion in $4+$ oxidation state
(T) $d^{4}$ species
[Given: Atomic number of $\mathrm{Cr}=24, \mathrm{Ru}=44, \mathrm{Fe}=26$ ]
Match each metal species in LIST-I with their properties in LIST-II, and choose the correct option
- A. I $\rightarrow$ R, T; II $\rightarrow$ P, S; III $\rightarrow$ Q, T; IV $\rightarrow$ P, Q
- B. I $\rightarrow$ R, S; II $\rightarrow$ P, T; III $\rightarrow$ P, Q; IV $\rightarrow$ Q, T
- C. I $\rightarrow \mathrm{P}, \mathrm{R} ; \mathrm{II} \rightarrow \mathrm{R}, \mathrm{S}$; III $\rightarrow \mathrm{R}, \mathrm{T}$; IV $\rightarrow \mathrm{P}, \mathrm{T}$
- D. I $\rightarrow$ Q, T; II $\rightarrow \mathrm{S}, \mathrm{T}$; III $\rightarrow \mathrm{P}, \mathrm{T}$; IV $\rightarrow \mathrm{Q}, \mathrm{R}$
Solution
The correct option is **A**.